Bab 5 Indeks dan Logaritma Posted on May 14, 2016 by user 5.5 Indeks dan Logaritma, SPM Praktis (Soalan Pendek) Soalan 9 Selesaikan persamaan, log 2 4x=1− log 4 x Penyelesaian: log 2 4x=1− log 4 x log 2 4x=1− log 2 x log 2 4 log 2 4x=1− log 2 x 2 2 log 2 4x=2− log 2 x log 2 16 x 2 = log 2 4− log 2 x log 2 16 x 2 = log 2 4 x 16 x 2 = 4 x x 3 = 4 16 = 1 4 x= ( 1 4 ) 1 3 =0.62996 Soalan 10 Selesaikan persamaan, log 4 x=25 log x 4 Penyelesaian: log 4 x=25 log x 4 1 log x 4 =25 log x 4 1 25 = ( log x 4 ) 2 log x 4=± 1 5 log x 4= 1 5 or log x 4=− 1 5 4= x 1 5 4= x − 1 5 x= 4 5 4= 1 x 1 5 x=1024 x 1 5 = 1 4 x= 1 1024 Soalan 11 Selesaikan persamaan, 2 log x 5+ log 5 x=lg1000 Penyelesaian: 2 log x 5+ log 5 x=lg1000 2. 1 log 5 x + log 5 x=3 ×( log 5 x )→ 2+ ( log 5 x ) 2 =3 log 5 x ( log 5 x ) 2 −3 log 5 x+2=0 ( log 5 x−2 )( log 5 x−1 )=0 log 5 x=2 or log 5 x=1 x= 5 2 x=5 x=25