Question 1
Solve the equation, log3 [log2(2x – 1)] = 2
Solution:
log3 [log2 (2x – 1)] = 2 ← (if log a N = x, N = ax)
log2 (2x – 1) = 32
log2 (2x – 1) = 9
2x – 1 = 29
x = 256.5
Question 2
Solve the equation,
Solution:
Question 3
Solve the equation,
Solution:
Question 4
Solve the equation,
Solution: