SPM Practice (Short Questions)


Question 1:


In figure above, FAD is a tangent to the circle with centre O. AEB and OECD are straight lines. The value of y is

Solution:

OAD = 90o
AOD= 180o  – 90o – 34o= 56o
y = 56o  ÷ 2 = 28o


Question 2:

In figure above, PQR is a tangent to the circle QSTU at and TUPV is a straight line. The value of y is

Solution:

QTS = ∠RQS = 40o
SQT= ∠QTS = 40o (isosceles triangle)
PQT= 180o  – 40o – 40o= 100o
TPQ= 180o  – 115o = 65o
y = 180o  – 100o – 65o= 15o


Question 3:


In figure above, ABC is a tangent to the circle BDE with centre O, at B.
Find the value of y.
 
Solution:
BOD= 2 × ∠BED
= 2 × 35o = 70o
ODB = ∠OBD
= (180– 70o÷ 2 = 55o

EDB = ∠ EBA = 75o
yo + ∠ ODB = 75o
yo + 55o = 75o
y = 20o