7.2.2 Geometrical Constructions, PT3 Focus Practice 2
Question 4:
Diagram below shows a parallelogram PQRS. The point T lies on PQ such that ST is perpendicular to PQ.
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture77-1-300x177.png)
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture77-1-300x177.png)
Using only a ruler and a pair of compasses, construct parallelogram PQRS, beginning from the lines PQ and PS provided in the answer space.
Answer:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture78-1-300x240.png)
Solution:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture79-1-300x244.png)
Question 5:
Diagram below shows a triangle ABC.
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture80-1-300x215.png)
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture80-1-300x215.png)
(a) Using only a ruler and a pair of compasses, construct triangle ABC, beginning with the straight line BC in the answer space.
(b) Hence, measure the length, in cm, of BA.
Answer:
(a)
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture81-1-300x49.png)
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture81-1-300x49.png)
Solution:
(a)
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2017/09/Picture82-2-300x146.png)
(b)
BA = 4.5 cm