Example 1:
Solution:
using gradient formulay2−y1x2−x19−45−(−1)=q−(−5)5−(−7)56=q+512
The straight lines MN and PQ in the diagram above are parallel. Find the value of q.
Solution:
If two lines are parallel, their gradients are equal.
m1 = m2
mMN = mPQ
using gradient formulay2−y1x2−x19−45−(−1)=q−(−5)5−(−7)56=q+512
60 = 6q + 30
6q = 30
q = 5