3.2.2 Circles II, PT3 Practice


3.2.2 Circles II, PT3 Practice

Question 6:
Diagram below shows a circle with centre O. POR is a straight line.

Find the value of x and of y.

Solution:
x=40×2=80y=180802=50


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Question 7:
Diagram below shows a circle with centre O.

Find the value of x.

Solution:
QRO=38o,ORS=44oQRS=38o+44o=82oxo=82o×2xo=164ox=164



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Question 8:
Diagram below shows a circle. QTS is the diameter of the circle and PTR is a straight line.
Find the value of x.

Solution:
RPS=90o42o=48oxo=48o+37o=85o



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Question 9:
Diagram below shows a circle with centre O. PQR is a straight line.

Find the value of x and of y.

Solution:
In cyclic quadrilateral,
Angle at Q = 180o – 70o = 110o
x2 = exterior angle at Q
= 180o – 110o
= 70o
x = 70

yo = reflex angle at O
yo = 360o – (70o × 2)
yo = 220o
y = 220


Question 10:
In diagram below, ABCD and DEFG are straight lines.
Find the value of x and of y.

Solution:
x=95(exterior of B cyclic quadrilateral)CBF+BFE+95o+110o=360o CBF+BFE+205o=360oCBF+BFE=155oyo+CBF+BFE=180o  yo+155o=180o  y=25

3.2.1 Circles II, PT3 Practice


3.2.1 Circles II, PT3 Practice

Question 1:
(a) In Diagram below, KLMLPN and MPO are straight lines.

 
Find the value of x and of y.

(b) In the diagram below, O is the centre of the circle. Find the value of

(i) x   (ii) y
 
Solution:
(a)
LOM=LNM=yo=44oy=44NMO=NLO=41oxo=180o80o41o=59o

(b)(i)
2x = 200o
x = 100o

(b)(ii)
+ y = 180o
100o + y = 180o
y = 80o


Question 2:
(a) In Diagram below, AOC and BCD are straight lines with centre O.
Find the value of y.

(b) In diagram below, ABCD is a circle with centre O and ADE is a straight line.

Find the value of y.

Solution:
(a)
AOB=45o×2=90oyo=180o90o=90o

(b)

ABD=12×100o=50oCDE=ABC=85oyo+50o=85oyo=35oy=35


Question 3:
(a)  In diagram below, ABCD is a circle. AEC and BED are straight lines.
 
Find the value of y.
 
(b) Diagram below shows a circle KLMN with centre O.
 
Find the value of x.

Solution:
(a)
ABE=ACD=45oyo=180o45o55oyo=80oy=80
 
(b)
OML=OLM=42o(xo+42o)+KNM=180oxo+42o+110o=180oxo+152o=180oxo=180o152oxo=28ox=28


Question 4:
Diagram below shows a semicircle ABCD with centre O.

It is given that AB = CD.
Find the value of y.

Solution:
y+ 32o + 32o + 90o = 180o
y= 180o – 154o
y= 26o
= 26


Question 5:
In diagram below, ABC and DEF are straight lines.

Find the value of x and of y.

Solution:
x+38=93        x=9338        x=55DBG=38o (GB=GD)       yo=DBG    y=38

3.1 Circles II


3.1 Circles II

(A) Properties of Circles Involving Symmetry, Chords and Arcs
 


(B) Identify the Properties of Chords
(1) A radius that is perpendicular to a chord divides the chord into two equal parts.
 

(C) Properties of Angles in Circles

(1)


(2)


(3)


(4)


(5)