4.2.2 Decimals, PT3 Practice


Question 5:
Calculate the value of 4 5 +15.4÷4 and express the answer correct to one decimal place. 

Solution:
4 5 +15.4÷4 = 4 5 +3.85 =0.8+3.85 =4.65 =4.7 (one decimal place)


Question 6:
Calculate the value of 84 – 3(14 + 48 ÷ 6) =

Solution:
843( 14+48÷6 ) =843[ 14+( 48÷6 ) ] =843( 14+8 ) =843( 22 ) =8466 =18


Question 7:
Calculate the value of  4×0.18 0.9 .

Solution:
4×0.18 0.9 = 0.72 0.9             = 0.72×10 0.9×10             = 7.2 9             =0.8


Question 8:
Calculate the value of ( 8.42.64 )÷ 4 3  and express the answer correct  to two decimal places.

Solution:
( 8.42.64 )÷ 4 3 = 5.76 1.44 × 3 4 =4.32

4.2.1 Decimals, PT3 Practice


Question 1:
62.4 – 36.02 + 12.6 =

Solution:



Question 2:
4.76 × 7.2 ÷ 0.3 =

Solution:
4.76×7.2÷0.3 =34.272÷0.3 = 34.272 0.3 = 34.272×10 0.3×10 = 342.72 3 =114.24





Question 3:
0.12 × (5.9 – 1.33) ÷ 0.8 =

Solution:
0.12×( 5.91.33 )÷0.8 =0.12×4.57÷0.8 =0.5484÷0.8 = 0.5484 0.8 = 0.5484×10 0.8×10 = 5.484 8 =0.6855




Question 4:
14.83 + (20.04 – 10.68) ÷ 1.8 =

Solution:
14.83+( 20.0410.68 )÷1.8 =14.83+9.36÷1.8 =14.83+ 9.36×10 1.8×10 =14.83+ 93.6 18 =14.83+5.2 =20.03