5.4 Equations Involving Logarithms (Example 2 & 3)

Example 2
Solve the following equation:
(a) logy813=logy3
(b) 2log2xlog2(x21)4=0









Example 3
Sole the following equation:
(a) log3[log2(2x1)]=2
(b) log16[log2(5x4)]=log93






5.4 Equations Involving Logarithms

METHOD:
  1. For two logarithms of the same base, if logam=logan , then m = n
  2. Convert to index form, if logam=n , then m = an.


Example 1
Solve the following equation:
(a) log32+log3(x+5)=log3(3x1)
(b) log28x3=log2(2x1)
(c) 3logx2+2logx4logx256=1








5.3 Equations Involving Indices (Example 5)


Example 5 (Unequal Base – put log both sides):
Solve each of the following.
(a) 3x+1=7
(b) 2(3x)=5
(c) 2x.3x=9x4
(d) 5x1.3x+2=10













5.3 Equations Involving Indices (Example 4)

Example 4 (Index Equation - Substitution)
Solve each of the following.
(a) 3x1+3x=12
(b) 2x+2x+3=72
(c) 4x+1+22x=20








5.3 Equations Involving Indices (Example 3)

Example 3 (Index Equation - Equal Base)
Solve each of the following.
(a) 27(813x)=1
(b) 81n+2=13n27n1
(c) 8x1=42x+3







5.3 Equations Involving Indices


METHOD:
  1. Comparison of indices or base
    1. If  the base are the same , when ax=ay , then x = y
    2. If  the index are the same , when ax=bx , then a = b

  2. Using common logarithm (If base and index are NOT the same)
ax=blgax=lgbx=lgblga


Example 1 (Index Equation - Equal base)
Solve each of the following.
(a) 16x=8
(b) 9x.3x1=81
(c) 5n+1=1125n1









Example 2 (Solving index equation simultaneously)
Solve the following simultaneous equations.

2x.42y=8

3x9y=127



5.2b Change of Base of Logarithms (Example 3 & 4)

Example 3
Given that logp3=h   and logp5=k  , express the following in term of h and or k.
(a) logp53

(b) log1575





Example 4
Given that log3x=b  , express logx9x in term of b.



5.2b Change of Base of Logarithms

Change of Base of Logarithms

   logab=logcblogca         and      logab=1logba     

Example 1
:
Find the value of the following:
a. log25100
b. log30.45

Answer:
(a)  log25100=log10100log1025=log10102log1025=21.3979=1.431(b)  log30.45=log100.45log103=0.34680.4771=0.727



Example 2
Find the value of the following.
(a) log48
(b) log1255
(c) log8127
(d) log1664





5.2a Laws of Logarithms (Example 3)

Example 3

Given that log74=0.712   and log75=0.827  , evaluate the following.
(a) log720
(b) log7114
(c) log70.8
(d) log728
(e) log7140
(f) log7100
(g) log70.25
(h) log73564